nazli's father buys a bar fridge with a mass of 30kg. he unloads the box containing the bar fridge and starts to push it towards the house. at first he has to push with a force of 135 N to get the box to start moving. once it is moving he has to exert a force of 120 N to keep it moving with a constant speed. for the box on the driveway, calculate the maximum coefficient of static friction?​

This did i unseated, sorry

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Make them both to where they have the denominator of 18that makes 3/2 equal 27/18 and 1/9 equal 2/18so now you have  27/18x+5=2/18subtract 5 from the other sideso now you have 27/18x+2/18-5then subtract 2/18 from 27/18 to get 25/18x=-5then divide 25/18 by -5 and your answer will be  -5/18

Two cars collide, lock bumpers and move together after the collision.this collision is known as perfectly inelastic collision.