Physics, 05.10.2019 21:30 gracerhodes6972

Consider the image above. vi = the initial velocity and vf = the final velocity. is there acceleration? explain your answer.
a) no. the initial and final velocities are the same.
b) yes. the ball had to slow down in order to change direction.
c) no. acceleration is the change in velocity. the ball's velocity is constant.
d) yes. even though the initial and final velocities are the same, there is a change in direction for the ball.

Consider the image above. vi = the initial velocity and vf = the final velocity. is there accelerati

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Answer from: marahsenno

According to the statements, the answer to the question is yes. Even though the initial and final velocities are the same, there is a change in direction for the ball (option D).

Acceleration is the change in velocity, which is a vector, according to the following equation:

$a = \frac{\Delta v}{\Delta t} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}}$

Where:

$v_{f}$ and $v_{i}$ is the final and initial velocity, respectively

$t_{f}$ and $t_{i}$ is the final and initial time, respectively

In the given image, we can see that the magnitude of the final and initial velocity is the same and that directions are opposites, so the acceleration would be:

$a =\frac{v_{f} - v_{i}}{\Delta t} = \frac{(-5 - 5) m/s}{\Delta t} = \frac{-10 m/s}{\Delta t}$

With this, we can rule out the options:

A. Although the initial and final velocities are the same, the directions are not.

B. The ball does not need to slow down to change direction.

C. The ball's velocity is not constant (the directions are different).

Therefore, the answer is option D.

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Consider the image above. vi = the initial velocity and vf = the final velocity. is there accelerati...

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