Workers use a force of 2125 N to push a piano weighing 8800 N up a 20.0 m long ramp. a.) How
much work is done on the piano by the workers in pushing it up the ramp?

b.) The piano is being
moved from street level to the second floor of a building. The second floor is 4.0 m above street level.
If the workers decide to lift the piano straight up by using ropes, how much work would they do?

c.) What is the efficiency of the ramp?

Figure it out

Explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s