A dart is thrown horizontally at a target's center that is 5.00 m, away. The dart hits the target 0.150 m below the targets center. What is the initial velocity of the dart?

  v₀ₓ = 28.6 m / s

Explanation:

This is a missile throwing exercise

          y = t - ½ g t²

as the dart is thrown horizontally the vertical velocity is zero (I go = 0)

          y = - ½ g t²

          t =

let's calculate

         t =

         t = 0.175 s

the expression for horizontal displacement is

         x = v₀ₓ t

         v₀ₓ = x / t

         v₀ₓ = 5.00 / 0.175

         v₀ₓ = 28.6 m / s

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever