Physics, 25.03.2021 16:50 thatcommondumbgirl

Two speakers that are 15.0 mproduce in-phase sound waves of frequency 250.Hz in a roomwhere the speed of sound is 340. m/s. A woman starts out at the midpoint between the two speakers. a.What does she hear at the midpoint, constructive or destructive interference?b. She now walks slowly towards one of the speakers. How far from the center must she walk before she first hears the sound reach a minimum intensity?c. How far from the center must she walk before she first hears the sound at a maximum intensity?d. How far from the center must she walk before the second time she hears the sound at the minimum intensity?

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Answer from: sarai47

a. Constructive interference.

b. $0.34\; \rm m$ .

c. $0.68\; \rm m$ .

d. $1.02\; \rm m$ .

Explanation:

Frequency of this sound wave: $f = 250\; \rm Hz = 250\; \rm s^{-1}$ .

Speed of this sound wave: $v = 340\; \rm m \cdot s^{-1}$ .

Calculate the wavelength of this sound wave:

$\begin{aligned} \lambda &= \frac{v}{f} \\ &= \fraac{340\; \rm m \cdot s^{-1}}{250\; \rms^{-1}} \approx 1.36\; \rm m\end{aligned}$ .

Path difference refers to the absolute value of the difference between:

the distance between the first source (the first speaker) and the observer, andthe distance between the second source (the second speaker) and the observer.

When the observer in this question is on the line between the two speakers at meters from the midpoint, the corresponding path difference would be $2\; d$ meters. (Add $d\!$ to the distance from the closer source, and subtract $d\!\!$ from the distance from the other source.)

The question states that sound from the two speakers are in-phase. In other words, at every instant, the sound wave from the two speakers are at the same phase at the position of each speaker.

Because wave from the two sources are in-phase at the source:

Constructive interference happens when the path difference is an integer multiple of wavelength ( $k\, \lambda$ , where

is an integer.) That includes:

, $\lambda$ , $2\, \lambda$ , etc.Destructive interference happens when the path difference is an one-half plus some integer multiple of wavelength ( $(k + 1/2) \, \lambda$ , where

is an integer.) That includes: $\lambda / 2$ , $3\, \lambda / 2$ , $5\, \lambda / 2$ , etc.

Path difference is when the observer is at the midpoint. That would correspond to constructive interference.

The first destructive interference (minimum intensity) corresponds to a path difference of $\lambda / 2$ . Along the line, that would be observed at $(1/2) \cdot (\lambda / 2) = 0.34\; \rm m$ from the midpoint.

The next constructive interference (maximum intensity) would be observed when path difference is $\lambda$ . Along the line, that would be observed at $(1/2)\cdot \lambda = 0.68\; \rm m$ from the midpoint.

The second destructive interference (minimum intensity) would be observed when path difference is $(1 + (1/2))\, \lambda$ . Along the line, that would be observed at $(1/2) \cdot ((3/2)\cdot \lambda) = 1.02\; \rm m$ from the midpoint.

Answer from: Quest

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i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!

Answer from: Quest

its a 5.5 n

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