A stuntman drives a car off of a parking garage. The car lands 68.38 meters away from the base of the garage. If the stuntman drove the car at 19 m/s, how tall is the parking garage?

63.43 m

Explanation:

Given

Car lands 68.38 m away from the base of the garage

Stuntman drove the car with speed

Since there is no acceleration in the horizontal direction, so there is no change in velocity

time taken to cover 68.38 m is 3.598 s

In this time car travels a vertical distance of h

Such that we can write

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

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