Four charges of equal charge+q are placed at the corners of a rectangle of sides a and b. What is the potential at the center of the rectangle if q = 2.0 uc, a = 3.0 cm, and b = 4.0cm?​

V = 32.2 10³ V

Explanation:

The electric potential is a scalar quantity given by the expression

          V = h ∑  

Let's find the distance from each corner to the center of the square, using Pythagoras' theorem

           r =

indicate that all charges have the same magnitude and the casticista from each scheme to the center is r

           V = k q ()

let's calculate

            r = ½ Ra 2² + 4²

            r = 2,236 m

           V = 9 10⁹ 2 10⁻⁶  4 / 2,236

           V = 32.2 10³ V

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explanation:

this is a good question! i'll do some research and come back when i have the answer!