Two identical R = 6.77 ohm light bulbs are is series circuit with a 17.8 volt battery. What is the power (watt) of both
glowing bulbs?

the power of the two light bulbs is 23.4 W

Explanation:

Given;

the resistance of the two identical light bulbs in series, R₁ and R₂ = 6.77 ohms and 6.77 ohms respectively

battery voltage , V = 17.8 V

The equivalent resistance of the two light bulbs, R = R₁ + R₂

R = 6.77 + 6.77

R = 13.54 ohms

The power of the two light bulbs is calculated as follows;

Therefore, the power of the two light bulbs is 23.4 W

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

it would be kevlar ^^