A toy car with a mass of 8 kg and velocity of 5 m/s to the right collides with a 5.28 kg car moving to the left with a velocity of 1.65 m/s. After the collision, the 8 kg car continues foward with a velocity of 0.5 m/s. What is the new velocity of the 5.28 kg car after the collision? Please Answer Quick And Show Work Please, Thank You.

This is what a calorimeter is used for simpler ex, to measure calories in food.

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

The relationship of both of them