A 2500kg automobile develops 30kW of power to drive with a constant velocity of 90km/h on a level ground. What power must it develop to drive up a 15 degree hill with the same velocity.

the power developed by the automobile is 7,764.57 W.

Explanation:

Given;

mass of the automobile, m = 2500 kg

initial power developed by the automobile, P₁ = 30 kW = 30,000 W

initial speed of the automobile, v₁ = 90 km/h = 25 m/s

inclination of the hill, θ = 15⁰

second speed of the automobile, v₂ = v₁Sinθ

The power developed by the automobile is calculated as;

P = Fv

Therefore, the power developed by the automobile is 7,764.57 W.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

explanation:

the masses of the objects and the distance between them