Una muestra de agua de 250g de agua se caliento desde 10°C hasta 60°C calcula la cantidad de calor absorbido por el agua el calor especifico del agua es de 4186J/Kj. K

Calor absorbido, Q = 52325 Joules

Explanation:

Dados los siguientes datos;

Masa = 250g to kg = 250/1000 = 0.25kg

Temperatura inicial, T1 = 10°C to Kelvin = 273 + 10 = 283K

Temperatura final, T2 = 60°C to Kelvin = 273 + 60 = 333K

Capacidad calorífica específica = 4186 j/kg.K.

Para encontrar la cantidad de calor necesaria;

La capacidad calorífica viene dada por la fórmula;

Dónde;

Q representa la capacidad calorífica o la cantidad de calor.

m representa la masa de un objeto.

c representa la capacidad calorífica específica del agua.

dt representa el cambio de temperatura.

dt = T2 - T1

dt = 333 - 283

dt = 50 K

Sustituyendo en la fórmula, tenemos;

Calor absorbido, Q = 52325 Joules

33: i think it’s b

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.