A solution which has a solid solute is saturated at 25°C. It is then heated to 35°C. There is no change in the appearance of the solution. What term would now be associated with this solution? A.
unsaturated

B.
saturated

C.
oversaturated

D.
supersaturated

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

i believe the answer is electric potential.

explanation: