A factory produces steel components for use by a number of different companies. The density of the steel used by the factory is 8000 kg/mº,
A partoutor steel oube produced by the factory has a side length of 5 em,
5 cm
5 cm
5cm
Calculate the mass of one of these cubes. Write your answer in
kilograms

1 kg

Explanation:

Since density ρ = m/v where m = mass of steel cube and v = volume of steel cube = L³ where L= side length of steel cube = 5 cm = 0.05 m

Now, m =  ρv =  ρL³

Since  ρ = 8000 kg/m³,

m = ρL³

= 8000 kg/m³ × (0.05 m)³

= 8000 kg/m³ × 0.000125 m³

= 1 kg

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

where is the photo and the answer choices?