A drone accelerates from rest to a speed of 300 m/s in 3 s. What is the acceleration of the drone? How far will the drone go?

(i) 100 m/s²

(ii) 450 m

Explanation:

From the question,

Using,

(i) a = (v-u)/t Equation 1

Where a = acceleration of the drone, v = final velocity of the drone, u = Initial velocity of the drone, t = time.

Given: v = 300 m/s, u = 0 m/s (from rest), t = 3 s

Substitute these values into equation 1

a = (300-0)/3

a = 300/3

a = 100 m/s²

Hence the acceleration of the drone is 100 m/s²

(ii) using,

s = ut+at²/2 Equation 2

Where s = distance traveled by the drone.

also substitute the values above into equation 2

s = 0(3)+100(3²)/2

s = 50×9

s = 450 m

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach