An aircraft has to fly between two cities, one of which is 600.0 km north of the other. The pilot starts from the southern city and encounters a steady 100.0 km/h wind that blows from the northeast. The plane has a cruising speed of 236.0 km/h in still air. In what direction (relative to east) must the pilot head her plane

72.57° North of east

Explanation:

From the given information:

We can compute the velocity plane that is related to the ground in air in the North direction as;

However, the velocity of the wind-related to the ground from the NorthEast  direction is;

Now,

Since the plane is moving with a 236 km/h speed in the Northeast direction;

Then;

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle