A car moves in a straight line such that for a short time it's velocity is defined by V = (9t+ 2t) m/s, where t
is in seconds. Determine its position and acceleration when t = 3s.
When t = 0, S=0​

s = 90 m

a = 56 m/s²

Explanation:

I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t

Position is the integral of differential velocities

s =

s = 3t³ + t² | from 0 to 3

s = 3(3)³ + 3² - (0) = 90 m

acceleration is the derivative of velocity

a = v' = 18t + 2

a(3) = 18(3) + 2 = 56 m/s²

answer: what are you talking about?

explanation: