In a double‑slit interference experiment, the wavelength is λ = 507 nm , the slit separation is d = 0.180 mm , and the screen is D = 33.0 cm away from the slits. What is the linear distance Δ x between the ninth order maximum and the second order maximum on the screen?

Ais the answer hope this

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j