How does the ratio of the battery (ΔVB / IB) compare to the resistance values of the resistor? Attempt to write an equation relating the (ΔVB / IB) ratio to R1, R2, and R3. (R1, R2, & R3 = resistors/lightbulbs)
(Ratio of the battery is 9:9)
(It's basically asking to write an equation relating the batteries resistance which is Voltage/I (current) to the resistors)

hugh ok

Explanation:

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

they should be similar or the same