An electric toy with a resistance of 2.50\,\Omega is operated by a 3.00\,\text{V} battery. (c) How much energy was delivered to the toy [over four hours]?

Energy = 51840 J = 51.84 KJ

Explanation:

The electrical energy delivered to the toy can be found out by the following formula:

where,

V = Voltage = 3 V

R = Resistance = 2.5 Ω

I = Current = V/R (Ohm's Law) = 3 V/2.5 Ω = 1.2 A

t = time = (4 h)(3600 s/1 h) =  14400 s

Therefore,

Energy = 51840 J = 51.84 KJ

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

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