center of the circle and m (BYC) = 40°,
m(<AXD)=120' and m(<ADB) =50°.
Physics, 18.04.2021 15:10 kevinvalencia01
B
О is the
center of the circle and m (BYC) = 40°,
m(<AXD)=120' and m(<ADB) =50°.
What is m(DOC) and m(DC)?
Figure 5.40
Answers: 1
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О is the
center of the circle and m (BYC) = 40°,
m(<AXD)=120' and m(<ADB) =50°.
center of the circle and m (BYC) = 40°,
m(<AXD)=120' and m(<ADB) =50°.
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