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Physics, 18.04.2021 21:30 alysiareyes

Una caja de 5.0 kg de masa, rueda por unplano inclinado habiendo un coeficiente de fricción cinética 0.35 entre la caja y el plano. El plano tiene un ángulo de inclinación de 35 grados como se muestra en la figura. La magnitud de la aceleración en m/s2
de la caja en el plano es:

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..
El peso mg se descompone en dos componentes, en la dirección "x" es mg sen del ángulo y en la dirección "y" es -- mg cos del ángulo.

PlantearF neta y = 0 para calcular la magnitud de la fuerza normal y la fuerza de fricción sobre la caja:
n =- mg cos del ángulo = 0 n=? fc= cociente de fricción cinética x n=?

Aplicar la 2da ley de Newton en la dirección x y despejar a : Fneta x = -fc + mg sen del ángulo = m ax. ax=?

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