Marcel is his two children, jacques and gilles, to balance on a seesaw so that they will be able to make it tilt back and forth without the heavier child, jacques, simply sinking to the ground. given that jacques, whose weight is w, is sitting at distance l to the left of the pivot, at what distance l1 should marcel place gilles, whose weight is w, to the right of the pivot to balance the seesaw?

In order for the childreen to be balance in the see saw, each torque they produce should be equal in order for them to balance. Torque is equal to mass times distance

Since jacques weight is W and at L

And gilles weight is w and at L1

wL1 = WL

L1 = WL/w is the position of gilles for them to balance

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation: