Abowling ball has a mass of 5 kg. what happens to its momentum when the speed increases from 1 m/s to 2 m/s?

a) the initial momentum is 5 kg m/s and the final momentum is 7 kg m/s
b) the initial momentum is 5 kg m/s and the final momentum is 3 kg m/s
c) the initial momentum is 5 kg m/s and the final momentum is 20 kg m/s
d) the initial momentum is 5 kg m/s and the final momentum is 10 kg m/s

The correct answer of this question is : D) The initial momentum is 5 kg m/s, and the final momentum is 10 kg m/s

EXPLANATION :

Before going to answer this question, first we have to understand the momentum.

The momentum of a body is the amount of motion contained in a body. Quantitatively momentum is the product of mass with velocity.

Mathematically momentum p = mv.

Here, m is the mass of the body, and v is the velocity of the body.

As per the question, the mass of the ball m = 5 Kg.

The initial velocity of the ball u = 1 m/s.

Hence, initial momentum = m × u

                                          = 5 Kg × 1 m/s

                                          = 5 Kg.m/s

The final velocity of the ball v = 2 m/s

Hence, final momentum p = m × v

                                            = 5 Kg × 2 m/s

                                            = 10 Kg.m/s                        [ans]

the answer would be c

answer; equivalent to a one(1) horsepower motor;