An unknown force is applied to a 12 kg. the force acts at an angle of 30 degrees above the horizontal. determine the force acting if the force acts for a horizontal displacement of 22 meters and increases the 12 kg mass's speed from 11 m/s to 26 m/s

First solve the time it takes to displace to 22 m D = 0.5( Vi – Vf)*t 22 m = 0.5 ( 11 + 26) t T = 1.1891 s Solve for acceleration D = vt + 0.5at^2 22 = (11)( 1.1891) + 0.5(1.1891^2)a A = 12.6169 m/s2   F = ma Since the work is only done in the horizontal direction F sin (30) = (12 kg) ( 12.6169 m/s2) F = 302.8056 N