Two 100 kg bumper cars are moving toward each other in opposite directions. car a is moving at 8 m/s and car b at –10 m/s when they collide head–on. if the resulting velocity of car b after the collision is 8 m/s, what is the velocity of car a after the collision?

(i saw this question was asked previously, but the person did not provide the correct

so car A will move with speed 10 m/s in opposite direction

Explanation:

As we know that when two cars collide then the momentum of two cars will remains conserved

so here we have

mass of two cars = 100 kg

speed of car A = 8 m/s

speed of car B = - 10 m/s

after collision the speed of car B = +8 m/s

now by momentum conservation equation

so we have

so we have

so car A will move with speed 10 m/s in opposite direction

answer: its c lololo

15.3 cos 65 degrees trig