Calculate the energy of the orange light emitted, per photon, by a neon sign with a frequency of 4.89 × 1014 hz.

3.24 x 10⁻¹⁹ Joule

Further explanation

Given:

A neon sign with a frequency of 4.89 x 10¹⁴ Hz.

Question:

The energy of the orange light emitted per photon (in joules).

The Process:

The energy of a photon is given by

E = energy in joulesh = Planck's constant 6.63 x 10⁻³⁴ Jsf = frequency of light in Hz (sometimes the symbol f is written as v)

Let us find out the energy of the orange light emitted per photon.

Thus, we get a result of

- - - - - - - - - -

Notes:

When an electron moves between energy levels it must emit or absorb energy. The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons. A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.Learn moreWhat is the charge on 1.0 kg of protons?  link Determine the density of our sun at the end of its lifetime link   Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays link  

Keywords: calculate, the energy of the orange light emitted, per photon, by a neon sign, frequency, Planck's constant