Achild pushes her toy across a level floor at a steady velocity of 0.50 m/s using an applied force of 2.0 n. if the weight of the toy is 8.0 n, what is the coefficient of sliding friction between the toy and the floor?
a. 0.25
b. 1.0
c. 4.0
d. 0.40

a. 0.25

Explanation:

The toy is moving across the floor at constant velocity - this means that its acceleration is zero.

According to Newton's second law, this means that the net force acting on the toy is zero:

(1)

because a=0.

The net force, in this case, consists of two forces acting in opposite directions:

- The applied force, F = 2.0 N

- The frictional force,

where is the coefficient of sliding friction and (mg)=8.0 N is the weight of the toy.

Therefore, the equation of the forces (1) becomes:

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.