Astone is dropped from a bridge and hits the pavement below in two seconds. what is the velocity of the stone when it hits the pavement?

a. 0.20 m/s
b. 19.6 m/s
c. 4.9 m/s
d. 9.8 m/s

We have: a = v/t
Here, t = 2 s  [ Given ]
a = 9.8 m/s²  [constant value for earth system ]

Substitute their values into the expression:
9.8 = v/2
v = 9.8 × 2
v = 19.6 m/s

In short, Your Answer would be Option B

Hope this helps!

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