Aplane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. assume that the plane reaches the required takeoff velocity at the end of the runway. what is the time tto needed to take off?

The time required to take off the plane at the end of the runway is .

Further explanation:

Here, we have to find the time needed to take off the plane.

Given:

The constant acceleration of the plane is  

Length of the runway is .

Formula and concept used:

The time required to take off the plane can be calculated by using the kinematic equation of the motion.

By using second kinematic equation of the motion,

                                                   ….. (1)

Here, is the length of the runway.

is the initial velocity.

is the initial velocity.

is the time required to take off the plane.

Initially plane was in the rest position. So, initial velocity of the plane will be zero.

Here, plane takes take off at the end of the runway. So, we will consider the distance travelled by the plane is equal to the length of the runway.

Calculation:

Substitute for , for and for in equation (1).

Multiply both the side by in the above equation.

Simplify the above equation,

Thus, the time required to take off the plane is .

Learn more:

1. Water is a compound: .

2. Acceleration of the box against the friction: .

3. Conservation of momentum .

Answer details:

Grade: Senior school

Subject: Physics

Chapter: Kinematics

Keyword:

Plane accelerates, constant acceleration, runway, takeoff velocity, end of the runway, time needed to take off, acceleration, deceleration, equation of motion, Newton’s laws and inertial law.

1= 26.17

2= 1.17

3=30.86

4=5.86

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