Satellite a orbits the earth at a height 3.00 times the earth's radius. satellite b orbits the earth at a height 2.00 times the earth's radius. what is the ratio of the period of satellite b to the period of satellite a?

a) 1 to √(3/2)^3

b) 1 to 3√(3/2)^2

c) 1 to √(2/3)^3

d) 1 to 3√(2/3)^2

*the "3√" represents a cubic root*
i think the answer is b, but i am not sure

The correct answer to this question is this one: "B) 1 to 3√(3/2)^2 "

The fact that Satellite A orbits the earth at a height 3.00 times the earth's radius and  Satellite B orbits the earth at a height 2.00 times the earth's radius. The ratio of the of the period of Satellite B to the period of Satellite A is 1 : 3√(3/2)^2 

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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