How many calories of heat must you remove if you want to lower the temperature of 350 g of steel from 18.0 °c to 12.0 °c? the specific heat of steel is 0.11 cal/g °
c.?

Heat to be removed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 350(0.11)(12.0 - 18.0)
Heat = -231 cal 

c

explanation:

i believe the answer is c and this is only worth 10 points you might wanna change it

because growing process had stoped after 4-5 year