Physics, 24.12.2019 03:31 kcarstensen59070

An ice cube is placed on a hot stove. which of these statements best describes how heat moves between the ice cube and the stove? (1 point)
a. heat moves from the ice cube to the stove through conduction.
b. heat moves from the stove to the ice cube through conduction.
c. heat moves from the ice cube to the stove through convection.
d. heat moves from the stove to the ice cube through convection.

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Answer from: nsjcbdhcb

B! Conduction is touch, so the heat traveled through touch from th stove to the ice cube, therefore melting it

Answer from: idc23

B. Heat moves from the stove to the ice cube through conduction.

Explanation:

There are three modes of heat transfer- conduction, convection and radiation.

When two objects which are not in thermal equilibrium come in contact, heat transfer takes place via conduction. The heat transfers from hotter object to the cooler one.

In convection, there is bulk movement of fluid which transfers heat from heat source to the the cooler region of the fluid.

Heat radiation can travel through vacuum from the source of heat.

In the given situation, ice cube is placed on a heat stove. There is a direct contact between the two objects. Heat would transfer from hot stove to cube till the two are in thermal equilibrium.

Answer from: Quest

The answer is a.first and third quarters

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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