The volume of an ideal gas is decreased from 5.0 l to 5.0 ml at a constant pressure of 2.0 atm. calculate the work associated with this process

The work is 9.99J.

Explanation:

The work associated with a process is given by the following formula:

In which W is the work, P is the pressure and is the difference of volume.

In this problem, we have that:

The volume of an ideal gas is decreased from 5.0 l to 5.0 ml. Each ml has 0.001l. So the volume of the ideal gas is decreased from 5.0l to 0.005l. So

.

Constant pressure of 2.0 atm. So .

The work is 9.99J.

15.3 cos 65 degrees trig

0.11 m/s and 0.28 m/s should be correct