What is the final speed of a skater who accelerates at a rate of 2.0m/s^2 from rest for 3.5s? show your work

7.0m/s

Explanation:

Acceleration is defined as the change in velocity of a body with respect to time.

Mathematically, Acceleration = Change in velocity/time

Change in velocity = Final velocity (v) - Initial velocity(u)

Acceleration = Final velocity - Initial velocity/time taken i.e a = v-u/t

Since the body starts from rest, its initial velocity will be zero i.e u = 0m/s

Final velocity/speed = ?

Acceleration = 2.0m/s²

Time taken = 3.5seconds

Substituting this values into the acceleration formula, we have;

2.0 = v - 0/3.5

7.0 = v

This shows that the final speed of the skater will be 7.0m/s

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west