Current 1 of 8.4 a runs for 240 seconds and then stops. current 2 is 10.5
a. how long does current 2 have to run to deliver the same amount of charge as current 1? 88.2 s 192 s 2016 s 21,000 s

The charge of a current in a given period of time is calculated by multiplying the current and the duration of that current. Since in the problem charge would be constant, we can relate the first conditions to the second conditions.

q = IT
q1 = q2
I1T1 = I2T2
8.4(240)=(10.5)(T2)
T2 = 192 seconds

The charge of a current in a given period of time is calculated by multiplying the current and the duration of that current. Since in the problem charge would be constant, we can relate the first conditions to the second conditions.

q = IT
q1 = q2
I1T1 = I2T2
8.4(240)=(10.5)(T2)
T2 = 192 seconds