A100 g ball moving to the right at 4.0 m/s collides head-on with a 200 g ball that is moving to the left at 3.0 m/s.

The speed of the combined balls after the collision is about 0.67 m/s to the left

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Complete Question:

A 100 g ball moving to the right at 4.0 m/s collides head-on with a 200 g ball that is moving to the left at 3.0 m/s.

If the collision is perfectly inelastic, what is the speed of the combined balls after the collision? What is the direction of the combined balls after the collision?

Given:

mass of first ball = m₁ = 100 g

mass of second ball = m₂ = 200 g

initial speed of first ball = u₁ = 4.0 m/s ( + sign means right direction )

initial speed of second ball = u₂ = -3.0 m/s ( - sign means left direction )

final speed of both balls = v₁ = v₂ = v ( perfectly inelatic collision )

Asked:

final speed of both balls = ?

Solution:

We will use Conservation of Momentum Law as follows:

Both balls are moving to the left at about 0.67 m/s.

Grade: High School

Subject: Physics

Chapter: Dynamics

6/12=1/2

step-by-step explanation: