How much heat energy is required to raise the temperature of 20 kilograms of water from 0°c to 35°c?

Q = 2926 kJ

Explanation:

Given that,

Initial temperature of water,

Final temperature of water,

Mass, m = 20 kg

To find,

Heat energy required to raise the temperature.

Solution,

Let Q is the heat energy required to raise the temperature. It is based on the concept of specific heat. The expression for the heat raised is given by :

c is the specific heat of water,

Q = 2926000 Joules

or

Q = 2926 kJ

So, the heat energy required to raise the temperature of water is 2926 kJ.