Physics, 31.01.2020 11:53 lopezma152

A–0.06 c charge that is pointing downward is placed in a uniform electric field with a strength of 200 n/c. what is the magnitude and direction of the force on the charge?

a. 12 n up
b. 12 n down
c. n up
d. n down

Answers: 1

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Answer from: math4863

We are given with
q = -0.06 C (downward)
E = 200 N/C

The magnitude is
0.06 (200) = 12 N

Since the charge is directed downwards, the direction of the force is upwards.
The answer is
A. 12 N up

Answer from: Rakeem458

Explanation:

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

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A–0.06 c charge that is pointing downward is placed in a uniform electric field with a strength of 2...