Awire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes·meter at a speed of 10.0 meters/second. what is the emf produced?

Given:
length of the wire = 0.20 meters
magnetic field strength = 0.45 newtons/amperes meter
speed = 10.0 meters per second

emf = B * l * v 
B = flux density ; l = length of the wire ; v = velocity of the conductor

emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds
emf = 0.90 volts

The emf produced is 0.90 volts.