1. a passenger in the rear seat of a car moving at a steady speed is at rest relative to

A passenger in the rear seat of a car moving at a steady speed is at rest relative to the front seat of the car.

Explanation: From the Newton's first law, if the object is moving with uniform speed or if the object is in a state of rest then it will remain in that state unless it is acted upon by the external force.

In the given situation, a passenger in the rear seat of a car moving at a steady speed is at rest relative to the front seat of the car because the front seat of the car is also at rest in the car relative to the passenger. Only the car is moving.

Therefore, a passenger in the rear seat of a car moving at a steady speed is at rest relative to the front seat of the car.

it about 600 mph from what i calculated

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz