For the equation 3cu + 8hno3 → 3cu(no3)2 + 2no + 4h2o, how many units of no3 are represented on the products side?

a) 2
b) 3
c) 6
d) 8

C) 6

Explanation:

We see that on the product side, the only substance containing some units of NO3 is

We see that there is a subscript _2 which means that we have 2 units of NO3, and then we can also see that there is a coefficient 3 in front of the substance, this means we should multiply by 3 the 2 units of NO3, so we get:

therefore we have 6 units of NO3 in total on the product side.

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