Abus is traveling with a uniform acceleration of 2.75 meters/second2. if the initial velocity of the bus is 16.5 meters/second, what will its velocity be after 9.00 seconds?

Final speed, v = 41.25 m/s

Explanation:

It is given that,

Acceleration of the bus,

Initial velocity of the bus, u = 16.5 m/s

We have to find the velocity (v) of the bus after 9 seconds.

The rate of change of velocity is called as the acceleration of the bus. Mathematically, it can be written as :

v = 41.25 m/s

So, the final speed of the bus after 9 seconds is 41.25 m/s

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need to see circuit to get time constant