Avertical spring with a spring constant value of 4500 n/m is compressed 60 cm. a 5.5 kg pumpkin is placed on the end of the spring, and the spring is released. to the nearest whole number, the pumpkin will rise how many meters.

First, we calculate for the force that is attributed to the pumpkin. That is 5.5 kg times the acceleration due to gravity which is equal to 9.8 m/s2. This gives us an answer of 53.9 N.

We then divide the calculated value with the constant given.

                                   d = 53.9 N / (4500 N/m) = 0.01197 m

Therefore, the spring was stretched for about 11.98 mm.

The correct answer is 15.

answer(20) psi;