The potential energy of a charge q moving from a to b at point a is 5.4 × 10-10 joules and at point b is 2.3 × 10-10 joules. the charge is 2.5 × 10-15 coulombs. what potential difference does the particle undergo?

potential difference = 124000 Volts

Explanation:

As we know that potential energy per unit charge is known as potential of the point.

So here we can say that

now we know that initial potential at point A is given as

now similarly potential at point B is given as

Now potential difference of two points is given as

it consists of the house of representatives and the senate.

explanation:

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .