Adiver of mass 101 kg jumps upward off a diving board into water. diving board is 6m above water. diver has a speed of 1.2m/s. based on speed how high above the board will the diver reach?

When the diver reaches maximum height, the upward velocity will be zero.

We shall use the formula
v^2 = u^2 - 2gh
where 
v = 0 (velocity at maximum height)
u = 1.2 m/s, intial upward velocity
g = -9.8 m/s^2, gravitational acceleration (downward)
h = maximum height attained above the diving board.

Therefore
0 = 1.2^2 - 2*9.8*h
h = 1.2^2/(2*9.8) = 0.0735 m

0.074 m (nearest thousandth)