Atelevision of mass 8kg sits on a table the coefficient of static friction between the table and television is .48 what is the minimum applied force that will cause the television to slide

Th normal reaction between the television and the table is
N = (8 kg)(9.8 m/s²) = 78.4 N

The static coefficient of friction is μ = 0.48.

When the television is about to slide on the table, the applied force should overcome the force due to static friction.

The applied force should be at least
F = μN
   = 0.48*78.4
   = 37.632 N

37.6 N (nearest tenth)

Divide 108.2 x 10^6 into 1.5 x 10 and the result will be in au (astronomical units)