You fill a graduated cylinder with 50.00 milliliters of water. you drop a piece of aluminum with a mass of 15.00 grams into the graduated cylinder causing the water to rise. what would the new volume of the graduated cylinder be after dropping the aluminum?

Note that 1 mL (milliliter) = 1 cm^3.

The volume of water is
Vw = 50.00 mL = 50 cm^3

From tables, the density of aluminum is 2.7 g/cm^3.

Because mass = density * volume, the volume of the aluminum is
Va = (15 g)/(2.7 g/cm^23) = 5.556 m^3

Because the aluminum sinks and displaces water in the cylinder, the new volume is the sum of the volume of water and the aluminum.
New volume = Vw + Va = 50 + 5.556 = 55.556 cm^3

 55.6 cm³ (nearest tenth)

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