N2 + 3h2 mc033-1.jpg 2nh3

what is the percent yield of nh3 if the reaction of 26.3 g of h2 produces 79.0 g of nh3?

N2+3H2->2NH3

When 3 moles of H2 react, they produce 2 moles of NH3

3 moles of H2 have a mass of 2.02 g

2 moles of NH2 have a mass of 17.0 g

So when 2.02 g H2 react, they produce 17.0 g NH3

If 26.3g H2 react with a yield of 100%, we expect…

2.02g H217.0gNH3

26.3g H2x=221gNH3

So now let’s calculate the percentage:

221gNH3­­­­­­­­100%

79.0gNH3x=79.0*100/221=35.7%

i need to show me the graph so i can give u an answer