An athlete pulls handle a to the left with a constant force of p = 125 n. knowing that after the handle a has been pulled 30.25 cm its velocity is 3.2 m/s, determine the mass of the weight stack
b. (round the final value to two decimal places.)

Two equations are used for this problem: Newton's 2nd law of motion, and also an equation derived from the 2nd law specialized for linear motion at constant acceleration.

(1) F = ma
(2) 2ax = v2^2 - v1^2

We will use equation 2 first:

2a(0.3025 m) = (3.2m/s)^2 - 0^2
a = 16.926 m/s^2

Using equation 1:

F = ma
125 N = m(16.926 m/s^2)
m = 7.39kg

Answer: buoyancy forceexplanation: in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.