Two point particles, one with charge +8 × 10–9 c and the other with charge–2 × 10–9 c, are separated by 4 m. the electric field midway between them is:

We can calculate for the electric field using the Coulombs law. The mathematical expression for this is:

F = k q1 q2 / r^2

Where,

F = force of electric field

k = Coulombs constant = 8.988 * 10^9 N m^2 / C^2

q = charge of one particle in absolute value

r = distance between the two charges  = 4 m

Substituting the given values to the equation:

F = (8.988 * 10^9 N m^2 / C^2) (8 * 10^-9 C) (2 * 10^-9 C) / (4 m)^2

F = 8.988 * 10^-9 N

The two charges attract with an electric field of 8.988 * 10^-9 N

the answer would be   dignified - apex